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Interface QuadraticBezierCurve

Create a smooth 2d quadratic bezier curve, defined by a startpoint, endpoint and a single control point.

Code Example

const curve = new THREE.QuadraticBezierCurve(
new THREE.Vector2( -10, 0 ),
new THREE.Vector2( 20, 15 ),
new THREE.Vector2( 10, 0 )
);
const points = curve.getPoints( 50 );
const geometry = new THREE.BufferGeometry().setFromPoints( points );
const material = new THREE.LineBasicMaterial( { color : 0xff0000 } );
// Create the final object to add to the scene
const curveObject = new THREE.Line( geometry, material );

Hierarchy

Index

Constructors

constructor

Properties

arcLengthDivisions

arcLengthDivisions: number

This value determines the amount of divisions when calculating the cumulative segment lengths of a curve via .getLengths. To ensure precision when using methods like .getSpacedPoints, it is recommended to increase .arcLengthDivisions if the curve is very large. Default is 200.

default

200

type

type: string
default

'QuadraticBezierCurve'

v0

The startpoint.

default

new THREE.Vector2()

v1

The control point.

default

new THREE.Vector2()

v2

The endpoint.

default

new THREE.Vector2()

Methods

clone

computeFrenetFrames

copy

fromJSON

getLength

  • getLength(): number

getLengths

  • getLengths(divisions?: number): number[]

getPoint

getPointAt

  • Parameters

    • u: number

      A position on the curve according to the arc length. Must be in the range [ 0, 1 ].

    • Optional optionalTarget: I3JS.Vector2

      If specified, the result will be copied into this Vector, otherwise a new Vector will be created.

    Returns I3JS.Vector2

    Returns a vector for a given position on the curve according to the arc length.

getPoints

getSpacedPoints

getTangent

  • Parameters

    • t: number

      A position on the curve. Must be in the range [ 0, 1 ].

    • Optional optionalTarget: I3JS.Vector2

      If specified, the result will be copied into this Vector, otherwise a new Vector will be created.

    Returns I3JS.Vector2

    Returns a unit vector tangent at t. If the derived curve does not implement its tangent derivation, two points a small delta apart will be used to find its gradient which seems to give a reasonable approximation.

getTangentAt

  • Parameters

    • u: number

      A position on the curve according to the arc length. Must be in the range [ 0, 1 ].

    • Optional optionalTarget: I3JS.Vector2

      If specified, the result will be copied into this Vector, otherwise a new Vector will be created.

    Returns I3JS.Vector2

    Returns tangent at a point which is equidistant to the ends of the curve from the point given in .getTangent.

getUtoTmapping

  • getUtoTmapping(u: number, distance: number): number
  • Given u in the range ( 0 .. 1 ), returns t also in the range ( 0 .. 1 ). u and t can then be used to give you points which are equidistant from the ends of the curve, using .getPoint.

    Parameters

    • u: number
    • distance: number

    Returns number

toJSON

  • toJSON(): object

updateArcLengths

  • updateArcLengths(): void

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